Thread: GMAT Geometry...etc.

I have been studying for the GMAT and GRE. I have taken a few GMAT CAT practice tests from the GMATprep software I downloaded from the GMAT website. I have managed to test to the level where the CAT software is giving me what it considers difficult questions. I have been stumped on a few and even after going back to review them I either don't see how to arrive at the correct answer or I haven't figured out the fastest way to solve the question. On average I should on spend 2 minutes per question. I will post a few of the problems below. The answer with the blue square is the correct answer. The filled in answer is what I choose. Thanks in advance for those that can help me out.

Frankly I have a great deal of trouble reading your posting.
But the correct answer to that question is:

I agree with Plato, the answer should be . Perhaps there is an error in the software's answers.

Incidentally, and unless I'm missing something, this problem shouldn't take more than 5 seconds to solve.

Patrick

I also answered s=square root of 3 but according to the software the answer is s=1. I think we both assumed the larger triangle was being bisected evenly.

I worked the problem using pythagoreon's thrm and the sides of the right triangle in the negative quadrant to find the length of the radius =2. Then the larger equilateral triangle has sides 2,2, 2 times square root 2 applying the knowledge that the ratio of a right equilateral triangle is 1:1:square root 2. Then S = (2 times square root 2) - (square root 3).

Thats where I am stuck. How do I get from subtracting these two square roots to the answer 1? Is there a simpler approach.

the graph shown is somewhat decieving, it is a 2 unit circle
(not a unit circle which is usually shown)

P is it appears to be more like

therefore on a unit circle P would be
and Q from P would be

So on a 2 unit circle P and Q

therefore s = 1

Makes sense. thanks

is 90 degrees
90 degress

Similar Triangles:

is equal to


Thus the y-coord of P is equal to the x-coord of Q.

.

Posted by Rick.81
The diagram you showed is depicted wrongly . the two points should be at different elevations If thats the way it was depicted I think it unfair.Putting in the perpendicular mark between the radii is a clue which leads to a correct solution and it is all in knowing the properties of 30-60-90 triangles.

bjhopper

Never assume such diagrams are drawn to scale. They are done that way to throw you off.