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  1. #1
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    geometry problems help

    1)
    A new flat screen TV is packaged in a box shaped like a rectangular prism with height 60cm and length 1m. The volume of the box is 240,000cm3. Determine the amount of cardboard required to construct the box in squared centimetres. (Assume no overlap of cardboard.)

    2)
    A new flat screen TV is packaged in a box shaped like a rectangular prism with height 60cm and length 1m. The volume of the box is 240,000cm3. Determine the amount of cardboard required to construct the box in squared centimetres. (Assume no overlap of cardboard.)
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  2. #2
    A riddle wrapped in an enigma
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    Quote Originally Posted by sri340 View Post
    1)
    A new flat screen TV is packaged in a box shaped like a rectangular prism with height 60cm and length 1m. The volume of the box is 240,000cm3. Determine the amount of cardboard required to construct the box in squared centimetres. (Assume no overlap of cardboard.)

    2)
    A new flat screen TV is packaged in a box shaped like a rectangular prism with height 60cm and length 1m. The volume of the box is 240,000cm3. Determine the amount of cardboard required to construct the box in squared centimetres. (Assume no overlap of cardboard.)
    Hi sri340,

    These two problems look identical to me. I don't get it.

    Use V=lwh, and substitute what you know.

    1 m = 100 cm

    240000 = 100 X w X 60

    Solve for w. We get 40 cm wide.

    Now we have:

    2 panels (100 X 60) cm^2 = 2(6000) cm^2 = 12000 cm^2

    2 panels (100 X 40) cm^2 = 2(4000) cm^2 = 8000 cm^2

    2 panels (60 X 40) cm^2 = 2(2400) cm^2 = 4800 cm^2

    Add 'em up.
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