[Refer to the attachment for picture]

Given an isoscles triangle ABC where AB = AC.

angle BAC = 20 (degrees)

angle EBC = 60

angle DCB = 50

Find angle DEB.

Hint: produce 2 other straight lines within triangle ABC.

Method being tried:

prove triangle ABE = isoscles

produce a line GE with G as a point on AD; assume GE = DE

prove triangles AGE and BDE = congruent (AAS)

prove GE // DC (not done yet...)

hence angle AEG = angle ACD = 30 (degrees)

hence angle DEB = 30 (degrees)

OR

produce the same line GE and assume that GE // DC, then prove triangle AGE congruent to BDE....

Thanks.