A cylindrical can of cleaner holds 1 L of liquid. What is its height if the diameter of the base is 12 cm? Round your answer to the nearest tenth of a cm.
A cylindrical can of cleaner holds 1 L of liquid. What is its height if the diameter of the base is 12 cm? Round your answer to the nearest tenth of a cm.
given Volume of cylindrical can,V = 1 L = 1000 cubic cm diameter of the base is 12 cm, therefore radius r=6 cm; height h = ?
$\displaystyle V=\pi r^2 h \quad \Rightarrow \quad h\ =\frac{V}{\pi r^2}$
substitute the values.....