Yes, negative 28 cannot be the area of the square.

Why?

Firstly, the area cannot be negative. There are no negative areas.

Secondly, the side of the square is 5+5 = 10cm. So, the area is 10*10 = 100 sq.cm.

The two identical circles touch each other on one point only--the midpoint of one of the side of the square.

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Edit.

Ooppss, sorry, I did not see the fine prints below the figure.

Now that I saw them, let me rectify my answer.

My poor eyesight cannot see which portion of the circle is shaded. (I think I have to buy a pair of all-seeing eyeglasses.) So let me assume that the portion in question is that portion not occupied by the circles.

The two circles occupied portions of the square that is a combined semicircle. (Two quadrants is one semicircle.)

Hence, area of shaded portion, A, is area of square of 10cm a side, minus (1/2)pi(5^2).

A = 10*10 -(1/2)pi(25)

A = 100 -39.27

A = 60.73 sq.cm. --------------answer.