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Math Help - triangles

  1. #1
    Senior Member
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    triangles

    ABCD is parallelogram where X is a point that lies on BD such that DX=3XB . AX extended meets BC at Y and DC is extebded to Z . Prove that triangle AXB is similar to triangle ZXD .

    Since ABCD is a prarallelogram , angle BAX = angle XZD .

    angle ABX = angle XDZ

    Then how can i make use of this information , DX=3XB to prove .

    DX\neq XB . But it's proportionate . So if the sides are proportionate , can i say that these triangles are congruent .
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  2. #2
    MHF Contributor red_dog's Avatar
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    You have to prove that the triangles are similar. But this is obviously because AB ia parallel to DZ.
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