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Math Help - Supplement & Complement

  1. #1
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    Supplement & Complement

    I been out of school for a weak because I had a appendix attack. Can you guys help me with these two so I can do the rest.

    1) The measure of a supplement of an angle is 12 more then twice the measure of the angle. Find the measures of the angle and supplement.

    2) A supplement of an angle is six times as large as a complement of the angle. Find the measures of the angle, its supplement, and its complement.

    Thanks
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  2. #2
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    Quote Originally Posted by FailedOnce View Post
    I been out of school for a weak because I had a appendix attack. Can you guys help me with these two so I can do the rest.

    1) The measure of a supplement of an angle is 12 more then twice the measure of the angle. Find the measures of the angle and supplement.

    2) A supplement of an angle is six times as large as a complement of the angle. Find the measures of the angle, its supplement, and its complement.

    Thanks
    Hi FailedOnce,

    I must assume you know the definition of complementary and supplementary angles.

    1) Let x = the measure of the angle

    Let 2x + 12 = the measure of its supplement

    x + 2x + 12 = 180

    2) Let x = the angle

    Let 90 - x = its complement

    Let 180 -x = its supplement

    180 - x = 6(90 - x)
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  3. #3
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    Thanks a lot!

    1)
    Measure of the Angle = 56
    Supplement of the angle = 124

    2)
    Measure of the Angle = 72
    Complement = 18
    Supplement = 108

    Still a little confusing on how to do it, I understand when looking at it, but I never would have guessed how to set it up.

    Let me try this one right here... Make sure I get it right?

    Question:
    Find the measure of an angle that is half as large as it's complement.

    Me Solving:
    Measure of the angle is x
    Measure of complement is 1/2(90-x)
    x=1/2(90-x)
    x=45-1/2x
    1.5x=45
    x=30

    Measure of the angle is 30

    I know this is a simple problem but did I set it up right?
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  4. #4
    A riddle wrapped in an enigma
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    Quote Originally Posted by FailedOnce View Post
    Thanks a lot!

    1)
    Measure of the Angle = 56
    Supplement of the angle = 124

    2)
    Measure of the Angle = 72
    Complement = 18
    Supplement = 108

    Still a little confusing on how to do it, I understand when looking at it, but I never would have guessed how to set it up.

    Let me try this one right here... Make sure I get it right?

    Question:
    Find the measure of an angle that is half as large as it's complement.

    Me Solving:
    Measure of the angle is x
    Measure of complement is (90-x) <==I removed the 1/2
    x=1/2(90-x) <==This says "The measure of the angle is half as large as its complement"
    x=45-1/2x
    1.5x=45
    x=30

    Measure of the angle is 30

    I know this is a simple problem but did I set it up right?
    You did great!!
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