# Supplement & Complement

• Oct 15th 2009, 09:45 AM
FailedOnce
Supplement & Complement
I been out of school for a weak because I had a appendix attack. Can you guys help me with these two so I can do the rest. (Worried)

1) The measure of a supplement of an angle is 12 more then twice the measure of the angle. Find the measures of the angle and supplement.

2) A supplement of an angle is six times as large as a complement of the angle. Find the measures of the angle, its supplement, and its complement.

Thanks
• Oct 15th 2009, 09:52 AM
masters
Quote:

Originally Posted by FailedOnce
I been out of school for a weak because I had a appendix attack. Can you guys help me with these two so I can do the rest. (Worried)

1) The measure of a supplement of an angle is 12 more then twice the measure of the angle. Find the measures of the angle and supplement.

2) A supplement of an angle is six times as large as a complement of the angle. Find the measures of the angle, its supplement, and its complement.

Thanks

Hi FailedOnce,

I must assume you know the definition of complementary and supplementary angles.

1) Let x = the measure of the angle

Let 2x + 12 = the measure of its supplement

x + 2x + 12 = 180

2) Let x = the angle

Let 90 - x = its complement

Let 180 -x = its supplement

180 - x = 6(90 - x)
• Oct 15th 2009, 10:21 AM
FailedOnce
Thanks a lot!

1)
Measure of the Angle = 56
Supplement of the angle = 124

2)
Measure of the Angle = 72
Complement = 18
Supplement = 108

Still a little confusing on how to do it, I understand when looking at it, but I never would have guessed how to set it up.

Let me try this one right here... Make sure I get it right?

Question:
Find the measure of an angle that is half as large as it's complement.

Me Solving:
Measure of the angle is x
Measure of complement is 1/2(90-x)
x=1/2(90-x)
x=45-1/2x
1.5x=45
x=30

Measure of the angle is 30

I know this is a simple problem but did I set it up right?
• Oct 15th 2009, 10:51 AM
masters
Quote:

Originally Posted by FailedOnce
Thanks a lot!

1)
Measure of the Angle = 56
Supplement of the angle = 124

2)
Measure of the Angle = 72
Complement = 18
Supplement = 108

Still a little confusing on how to do it, I understand when looking at it, but I never would have guessed how to set it up.

Let me try this one right here... Make sure I get it right?

Question:
Find the measure of an angle that is half as large as it's complement.

Me Solving:
Measure of the angle is x
Measure of complement is (90-x) <==I removed the 1/2
x=1/2(90-x) <==This says "The measure of the angle is half as large as its complement"
x=45-1/2x
1.5x=45
x=30

Measure of the angle is 30

I know this is a simple problem but did I set it up right?

You did great!!(Clapping)