1. ## Determine Angle X.

Kind of stuck here. And would really appreciate a couple of tips and clues or a couple of sentences of what is given/obvious.

2. $\displaystyle m\left( {\angle EAD} \right) = \frac{\pi }{6}$. WHY?
$\displaystyle m\left( {\angle ADE} \right) = m\left( {\angle DEA} \right)$ WHY?
$\displaystyle m\left( {\angle ADE} \right) + m\left( {\angle DEA} \right) + m\left( {\angle EAD} \right) = ?$

3. Originally Posted by Plato
$\displaystyle m\left( {\angle EAD} \right) = \frac{\pi }{6}$. WHY?
$\displaystyle m\left( {\angle ADE} \right) = m\left( {\angle DEA} \right)$ WHY?
$\displaystyle m\left( {\angle ADE} \right) + m\left( {\angle DEA} \right) + m\left( {\angle EAD} \right) = ?$

Thanks. But that wasn't much help to me. Can somone please explain and lead me to the correct answer.

4. Originally Posted by kevin3000
Thanks. But that wasn't much help to me. Can somone please explain and lead me to the correct answer.
Well that hurts my feelings. Did you think about it at all?
$\displaystyle \Delta EAB$ is equilateral so that tells you $\displaystyle m\left( {\angle EAB} \right)$.
So that tells you $\displaystyle m\left( {\angle EAD} \right)$.
The $\displaystyle \Delta EAD$ is isosceles. That gives you $\displaystyle x$.

5. Originally Posted by Plato
Well that hurts my feelings. Did you think about it at all?
$\displaystyle \Delta EAB$ is equilateral so that tells you $\displaystyle m\left( {\angle EAB} \right)$.
So that tells you $\displaystyle m\left( {\angle EAD} \right)$.
The $\displaystyle \Delta EAD$ is isosceles. That gives you $\displaystyle x$.
Thanks. But I need more help to be able to solve it

6. Originally Posted by kevin3000
Thanks. But I need more help to be able to solve it
Please show your attempt in light of the help given so far. What have you done, where do you get stuck?

7. if you will ONLY read well the post of Mr. PLATO, you almost there.

observe that, angle DAE = angle DAB - angle EAB = 90 - 60 = 30 degrees

but angle DAE is isoceles triangle.

Sum up the angles of triangle DAE, here we go

180 = (angle DAE) + (angle ADE) + (angle AED),

Therefore ....

8. Originally Posted by pacman
if you will ONLY read well the post of Mr. PLATO, you almost there.

observe that, angle DAE = angle DAB - angle EAB = 90 - 60 = 30 degrees

but angle DAE is isoceles triangle.

Sum up the angles of triangle DAE, here we go

180 = (angle DAE) + (angle ADE) + (angle AED),

Therefore ....

Thanks. Great! I understand perfectly!

9. i'm glad you solve it now . . . .