1. ## Perpendicular

Could some body please check this for me, and help where i might have gone wrong?

A(3,4) & B(-3,2)

The slope of line through A & B is:

$\displaystyle \frac {(2-4)}{((-3)-3)} = \frac {-2}{-6} = \frac {1}{3}$

Hence the midpoint

$\displaystyle ( \frac{1}{2} ( 3 + (-3)), \frac {1}{2} (4 + 2)) = (0,3)$

So the equation of the perpendicular bisector of AB is:

$\displaystyle y - 3 = -3(x - 0) y - 3 = -3x y = -3x + 3$

Is this correct?

Thank you

Could some body please check this for me, and help where i might have gone wrong?

A(3,4) & B(-3,2)

The slope of line through A & B is:

$\displaystyle \frac {(2-4)}{((-3)-3)} = \frac {-2}{-6} = \frac {1}{3}$

Hence the midpoint

$\displaystyle ( \frac{1}{2} ( 3 + (-3)), \frac {1}{2} (4 + 2)) = (0,3)$

So the equation of the perpendicular bisector of AB is:

$\displaystyle y - 3 = -3(x - 0)~~~ y - 3 = -3x~~~ y = -3x + 3$

Is this correct? YES
Yes

3. you are correct

or (0, 3) indicates that b = 3 as y - intercept and m = 2,

y = mx + b = 2x + 3 indeed is a solution