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Math Help - Perpendicular

  1. #1
    ADY
    ADY is offline
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    Perpendicular

    Could some body please check this for me, and help where i might have gone wrong?

    A(3,4) & B(-3,2)

    The slope of line through A & B is:


    \frac {(2-4)}{((-3)-3)} = \frac {-2}{-6} = \frac {1}{3}

    Hence the midpoint

    ( \frac{1}{2} ( 3 + (-3)), \frac {1}{2} (4 + 2)) = (0,3)

    So the equation of the perpendicular bisector of AB is:

    y - 3 = -3(x - 0)<br />
y - 3 = -3x<br />
y = -3x + 3

    Is this correct?

    Thank you
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  2. #2
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    Quote Originally Posted by ADY View Post
    Could some body please check this for me, and help where i might have gone wrong?

    A(3,4) & B(-3,2)

    The slope of line through A & B is:


    \frac {(2-4)}{((-3)-3)} = \frac {-2}{-6} = \frac {1}{3}

    Hence the midpoint

    ( \frac{1}{2} ( 3 + (-3)), \frac {1}{2} (4 + 2)) = (0,3)

    So the equation of the perpendicular bisector of AB is:

    y - 3 = -3(x - 0)~~~<br />
y - 3 = -3x~~~<br />
y = -3x + 3

    Is this correct? YES
    Yes
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  3. #3
    Senior Member pacman's Avatar
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    you are correct

    or (0, 3) indicates that b = 3 as y - intercept and m = 2,

    y = mx + b = 2x + 3 indeed is a solution
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