The gradient of the tangent to a curve at the point (x,y) where x>3, is inversely proportional to (x-3), and the curve passes through the points (4,0) and (6,ln9). Show that the equation of the curve is y=2ln(x-3).
Thanks
The gradient of the tangent to a curve at the point (x,y) where x>3, is inversely proportional to (x-3), and the curve passes through the points (4,0) and (6,ln9). Show that the equation of the curve is y=2ln(x-3).
Thanks