There are two problems based on similarity of triangles in RD Sharma for 10th
1. D is the mid point of side BC of a triangle ABC.AD is bisected at point E and BE produced cuts AC at X. Prove that BE:EX=3:1.
2.ABCD is parallelogram and APQ is a straight line meeting BC at P and DC produced at Q.Prove that the rectangle obtained by BP and DQ is equal to rectangle obtained by AB & BC.
NO FIGURES HAVE BEEN PROVIDED FOR BOTH.