Hello, anshulbshah!

Seven congruent rectangles form a bigger rectangle as shown in the diagram.

If the area of the bigger rectangle is 336 square units,

what is the perimeter of the bigger rectangle? Code:

y y y y
* - - - - - * - - - - - * - - - - - * - - - - - *
| | | | |
| | | | |
| | | | |
x | | | | | x
| | | | |
| | | | |
| | | | |
* - - - - - * - * - - - * - - - * - * - - - - - *
| | | |
| | | |
y | | | | y
| | | |
| | | |
* - - - - - - - * - - - - - - - * - - - - - - - *
x x x

Let: .

From the top and bottom edges of the rectangle,

. . we see that: . .[1]

The length of the big rectangle is:

The width of the big rectanble is:

. . Hence, its area is: .

We are told that the area is 336 unitsē.

. . So we have: . .[2]

Substitute [1] into [2]: .

. .

Substitute into [1]: .

The length of the big rectangle is: .

The width of the big rectangle is: .

Therefore, the perimeter is: . units.

Edit: Too slow again . . .