Hello, anshulbshah!
Seven congruent rectangles form a bigger rectangle as shown in the diagram.
If the area of the bigger rectangle is 336 square units,
what is the perimeter of the bigger rectangle? Code:
y y y y
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x | | | | | x
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* - - - - - * - * - - - * - - - * - * - - - - - *
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y | | | | y
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* - - - - - - - * - - - - - - - * - - - - - - - *
x x x
Let: .
From the top and bottom edges of the rectangle,
. . we see that: . .[1]
The length of the big rectangle is:
The width of the big rectanble is:
. . Hence, its area is: .
We are told that the area is 336 unitsē.
. . So we have: . .[2]
Substitute [1] into [2]: .
. .
Substitute into [1]: .
The length of the big rectangle is: .
The width of the big rectangle is: .
Therefore, the perimeter is: . units.
Edit: Too slow again . . .