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Thread: Finding the measure of angles...

  1. #1
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    Question Finding the measure of angles...

    For an acute angled triangle,all its angles have measure in integral degree.The smallest angle has a mesure 1/5th the measure of largest.Find all the measures of triangle>>
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  2. #2
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    Hello anshulbshah
    Quote Originally Posted by anshulbshah View Post
    For an acute angled triangle,all its angles have measure in integral degree.The smallest angle has a mesure 1/5th the measure of largest.Find all the measures of triangle>>
    You can't solve problems like this by simple algebra - you have to use a little bit of 'trial and error'.

    First, let's suppose the smallest angle is x^o. Then the largest angle is 5x. Since the triangle is acute-angled, 5x < 90\Rightarrow 5x \le 85, since x must be an integer, and 5x therefore a multiple of 5. This gives us that 0<x\le 17.

    Next suppose that the third (middle-sized) angle of the triangle is y^o. Using the angle-sum of a triangle, y = 180 - 6x. The smallest possible value of y is when x is as large as possible; i.e. x = 17\Rightarrow y = 180 - 102 = 78, and at this value the largest angle is 5x=85^o.

    If we make x a bit smaller, say x = 16, then y = 180 - 96 = 84. But in this case 5x = 80, which is smaller than y.

    So the only solution is 17^o,78^o,85^o.

    Grandad
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