Thread: Please help with this one...

I is the incenter o a triangle ABC. P is the point of intersection of angle bisector AI of the angle A and the circumcircle of the triangle other than A. Prove that PB=PC=PI

Let AI intersect the circle at D


Since, angle BAD=angle CAD
the arce BD and CD are equal
which implies chords BD and CD are equal.

thanks for ur reply...but could you please give a diagram....

Here I have attached figure....not so clear