I is the incenter o a triangle ABC. P is the point of intersection of angle bisector AI of the angle A and the circumcircle of the triangle other than A. Prove that PB=PC=PI

Results 1 to 4 of 4

- September 30th 2009, 08:46 AM #1

- Joined
- Sep 2009
- From
- Vadodara,Gujarat,India
- Posts
- 33

## Please help with this one...

I is the incenter o a triangle ABC. P is the point of intersection of angle bisector AI of the angle A and the circumcircle of the triangle other than A. Prove that PB=PC=PI

- October 1st 2009, 03:29 AM #2

- October 1st 2009, 03:55 AM #3

- Joined
- Sep 2009
- From
- Vadodara,Gujarat,India
- Posts
- 33

- October 1st 2009, 03:59 AM #4