BD is the median through the right angle af the triangle. Then $\displaystyle BD=AD=DC$. But $\displaystyle AB=BD$, then the traingle is equilateral. That means $\displaystyle \widehat{CAB}=60^{\circ}$
BD is the median through the right angle af the triangle. Then $\displaystyle BD=AD=DC$. But $\displaystyle AB=BD$, then the traingle is equilateral. That means $\displaystyle \widehat{CAB}=60^{\circ}$
please explain sir, how BD = AD? your answer is correct