In the figure above, CD is the diameter which meets the chord AB in E such that AE=BE=4cm. If CE = 3cm, find the radius of the circle.
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I've modified your drawing (see attachment)
You are dealing actually with a right triangle. The height divide the hypotenuse into 2 parts, called p and q. Then the product of these parts equals the square of the height (height theorem of a right triangle(?))
. Plug in the values you know: h = 4, q = 3
. Therefore the hypotenuse c = p + q: