Results 1 to 10 of 10

Math Help - Square

  1. #1
    Banned
    Joined
    Jan 2007
    Posts
    315

    Square

    A wire of length x is bent into the shape of a square.

    (a) Express the perimeter of the square as a function of x.

    (b) Express the area of the square as a function of x.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Global Moderator

    Joined
    Nov 2005
    From
    New York City
    Posts
    10,616
    Thanks
    9
    Quote Originally Posted by symmetry View Post
    A wire of length x is bent into the shape of a square.

    (a) Express the perimeter of the square as a function of x.

    Each side is of equal length and there are 4 sides thus, \frac{x}{4}.
    (b) Express the area of the square as a function of x.
    From (a) we have,
    A=\frac{x}{4} \cdot \frac{x}{4}=\frac{x^2}{16}.
    Because area is side squared.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Banned
    Joined
    Jan 2007
    Posts
    315

    ok

    Since all sides of the square are the same length, we have a square with x sides.

    The perimeter of a square is P = 4x, right?

    How did you get (x/4) = P?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    MHF Contributor Quick's Avatar
    Joined
    May 2006
    From
    New England
    Posts
    1,024
    Sorry, your Web browser is not Java compatible. This prototype will not be of much interest to you.
    Quote Originally Posted by symmetry View Post
    A wire of length x is bent into the shape of a square.

    (a) Express the perimeter of the square as a function of x.

    (b) Express the area of the square as a function of x.


    I'm a bit late. But here's a diagram



    You can clearly see the perimeter is "x"


    But You have to press the buttons to see anything (or you could move the red points too)
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Banned
    Joined
    Jan 2007
    Posts
    315

    ok

    What diagram? No picture came out with your reply.
    Follow Math Help Forum on Facebook and Google+

  6. #6
    MHF Contributor Quick's Avatar
    Joined
    May 2006
    From
    New England
    Posts
    1,024
    Quote Originally Posted by symmetry View Post
    What diagram? No picture came out with your reply.
    hmmm, it seems you don't see the java program. Did you at least see
    Sorry, your Web browser is not Java compatible. This prototype will not be of much interest to you.
    Follow Math Help Forum on Facebook and Google+

  7. #7
    Banned
    Joined
    Jan 2007
    Posts
    315

    ok

    Why don't you ask earboth what he uses to paste diagrams with his answers. I would like to know how to do that myself.

    Getting back to the question, why is P = (x/4)?
    Follow Math Help Forum on Facebook and Google+

  8. #8
    Forum Admin topsquark's Avatar
    Joined
    Jan 2006
    From
    Wellsville, NY
    Posts
    9,668
    Thanks
    298
    Awards
    1
    Quote Originally Posted by symmetry View Post
    Why don't you ask earboth what he uses to paste diagrams with his answers. I would like to know how to do that myself.

    Getting back to the question, why is P = (x/4)?
    You misunderstood what TPH was trying to do. The length of the wire is x. Thus the perimeter of the square is P = x. So one side of the square has a length of x/4. This is what TPH was saying.

    -Dan
    Follow Math Help Forum on Facebook and Google+

  9. #9
    MHF Contributor Quick's Avatar
    Joined
    May 2006
    From
    New England
    Posts
    1,024
    Quote Originally Posted by symmetry View Post
    Why don't you ask earboth what he uses to paste diagrams with his answers. I would like to know how to do that myself.
    When posting, go to the "manage attachments" button. Click, upload your attachments, and then it shows your attachment (which is usually a picture).

    The reason I used the java diagram is because it is more visual.
    Follow Math Help Forum on Facebook and Google+

  10. #10
    Banned
    Joined
    Jan 2007
    Posts
    315

    ok

    Thanks for the TIP QUICK.

    To the rest, I thank you all for your replies and wonderful math notes.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 3
    Last Post: July 2nd 2011, 07:03 PM
  2. perfect square trinomial/square of binomial
    Posted in the Algebra Forum
    Replies: 2
    Last Post: March 3rd 2011, 04:02 PM
  3. Replies: 1
    Last Post: November 24th 2009, 08:17 AM
  4. Replies: 11
    Last Post: October 25th 2009, 06:45 PM
  5. [SOLVED] Deriving a square root under a square
    Posted in the Calculus Forum
    Replies: 4
    Last Post: September 29th 2007, 06:21 AM

Search Tags


/mathhelpforum @mathhelpforum