A wire of length x is bent into the shape of a square.

(a) Express the perimeter of the square as a function of x.

(b) Express the area of the square as a function of x.

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- January 22nd 2007, 01:43 PMsymmetrySquare
A wire of length x is bent into the shape of a square.

(a) Express the perimeter of the square as a function of x.

(b) Express the area of the square as a function of x. - January 22nd 2007, 02:17 PMThePerfectHacker
- January 22nd 2007, 03:33 PMsymmetryok
Since all sides of the square are the same length, we have a square with x sides.

The perimeter of a square is P = 4x, right?

How did you get (x/4) = P? - January 22nd 2007, 06:17 PMQuick
- January 23rd 2007, 02:29 AMsymmetryok
What diagram? No picture came out with your reply.

- January 23rd 2007, 02:35 AMQuick
- January 23rd 2007, 02:37 AMsymmetryok
Why don't you ask earboth what he uses to paste diagrams with his answers. I would like to know how to do that myself.

Getting back to the question, why is P = (x/4)? - January 23rd 2007, 04:55 AMtopsquark
- January 23rd 2007, 08:56 AMQuick
- January 25th 2007, 03:24 PMsymmetryok
Thanks for the TIP QUICK.

To the rest, I thank you all for your replies and wonderful math notes.