Finally, the last geometry problem I am stuck with. Please help me get this one too! Thanks so much to anyone who helps, I am certain this involves similarity and congruence.
Follow Math Help Forum on Facebook and Google+
We have $\displaystyle OE=2OD$. But $\displaystyle OE=\frac{AC}{2}, \ OD=\frac{BC}{2}$. Then $\displaystyle AC=2BC$. Use Pitagora's theorem: $\displaystyle AC^2+BC^2=AB^2$. Replace BC with $\displaystyle \frac{AC}{2}$ and AB with 10 and find AC.
View Tag Cloud