Deductive geometry

**BG5965** · September 24th 2009, 05:15 AM

Finally, the last geometry problem I am stuck with. Please help me get this one too!

Thanks so much to anyone who helps, I am certain this involves similarity and congruence.

**red_dog** · September 24th 2009, 06:58 AM

We have $OE=2OD$ .

But $OE=\frac{AC}{2}, \ OD=\frac{BC}{2}$ .

Then $AC=2BC$ .

Use Pitagora's theorem: $AC^2+BC^2=AB^2$ .

Replace BC with $\frac{AC}{2}$ and AB with 10 and find AC.

Thread: Deductive geometry - Similarity and congruence

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