# Math Help - Deductive Geometry - Cyclic Quadrilaterals Help

1. ## [Solved] Deductive Geometry - Cyclic Quadrilaterals Help

Hi, here is the question and diagram.

I know that OECD is a cyclic quadrilateral, but I'm not sure how to work from there.

Thanks for helping, BG

2. Originally Posted by BG5965
Hi, here is the question and diagram.

I know that OECD is a cyclic quadrilateral, but I'm not sure how to work from there.

Thanks for helping, BG
$\angle AEO= \angle OAE$ as $\triangle AOE$ is equilateral

This implies that $\angle DEB = \angle EBD$ since $\angle CAB+\angle ABC= 90^{\circ}$ and $\angle AEO+ \angle DEB=90^{\circ}$.

CB