Express the area A of an isosceles right triangle as a function of the length x of one of the two equal sides.
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The hypotenuse is and this is a 45-45-90 Triangle. Thus, the equal sides are That means the area is,
Great but tell me: how did you get x/sqrt{2}? Shouldn't we RATIONALIZE the denominator?
Originally Posted by symmetry Express the area A of an isosceles right triangle as a function of the length x of one of the two equal sides. Hello, an isosceles right triangle is the half of a square. Area of the square: . Therefore the area of the isosceles right triangle: EB
Originally Posted by earboth Hello, an isosceles right triangle is the half of a square. Area of the square: . Therefore the area of the isosceles right triangle: EB of course you could just say that the area of a triangle is So:
What a great reply! I thank you. Earboth, Tell me, how do you make lovely geometric pictures?
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