The points A and B lie on the line y=12x / 5

The point D divides the interval AB into the ratio AD : DB = 3 : 2

C is the point (24, -10)

Area of triangle is 845 square units.

I have found that

CD = 26 (I am assuming D is perpendicular C)

by using | ax + by + c| / sqrt(a^2 + b^2) [I first put the line equitation into general form then plugged away]

AB = 65

From 1/2 x AB x CD = 845

I do not know how to find the perimeter of this triangle, as shown below:

Any help would be great. Exam tomorrow