Thread: Find Line Segment AB

In right triangles ABC and EDC, we have line segment BCD, AC is perpendicular to EC, BD = 10, CE = 8 and the measure of angle ACB = 30 degrees. What is the length of line segment AB?

(a) 2(sqrt{3})

(b) 3

(c) 3(sqrt{3})

(d) 6

I selected choice (d) but the book's answer is choice (a).

Originally Posted by sharkman

In right triangles ABC and EDC, we have line segment BCD, AC is perpendicular to EC, BD = 10, CE = 8 and the measure of angle ACB = 30 degrees. What is the length of line segment AB?

(a) 2(sqrt{3})

(b) 3

(c) 3(sqrt{3})

(d) 6

I selected choice (d) but the book's answer is choice (a).

is there a diagram with the question?

Originally Posted by skeeter

is there a diagram with the question?

Yes, but I don't know how to draw it here.

Originally Posted by sharkman

Yes, but I don't know how to draw it here.

sketch it using windows "paint" and upload as an attachment.

Originally Posted by sharkman

In right triangles ABC and EDC, we have line segment BCD, AC is perpendicular to EC, BD = 10, CE = 8 and the measure of angle ACB = 30 degrees. What is the length of line segment AB?

(a) 2(sqrt{3})

(b) 3

(c) 3(sqrt{3})

(d) 6

I selected choice (d) but the book's answer is choice (a).

This is my first trial of using "paint"

If that is correct:

CD = 8 cos(60deg) = 4
&
AB = (10-4)tan(30deg) =

Thank you all for the help.

Originally Posted by skeeter

sketch it using windows "paint" and upload as an attachment.

I did not know I can do that here.

Thanks

Originally Posted by aidan

This is my first trial of using "paint"

If that is correct:

CD = 8 cos(60deg) = 4
&
AB = (10-4)tan(30deg) =

That is correct!