A square with a side length of 5 has one vertex at (2, 0). Which of the following points cannot be a vertex of the square? A) (7, 0) B) (0, 7) C) (–3, 0) D) (–3, –5) E) (7, –5)
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Originally Posted by Robby A square with a side length of 5 has one vertex at (2, 0). Which of the following points cannot be a vertex of the square? A) (7, 0) B) (0, 7) C) (–3, 0) D) (–3, –5) E) (7, –5) an adjacent vertex will be 5 units away from (2,0) an opposite vertex will be units from (2,0) use the distance formula ...
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