# Math Help - A square with a side length of 5 has one vertex at (2, 0). Which of the following poi

1. ## A square with a side length of 5 has one vertex at (2, 0). Which of the following poi

A square with a side length of 5 has one vertex at (2, 0). Which of the following points cannot be a vertex of the square?

A) (7, 0)
B) (0, 7)
C) (–3, 0)
D) (–3, –5)
E) (7, –5)

2. Originally Posted by Robby
A square with a side length of 5 has one vertex at (2, 0). Which of the following points cannot be a vertex of the square?

A) (7, 0)
B) (0, 7)
C) (–3, 0)
D) (–3, –5)
E) (7, –5)
an adjacent vertex will be 5 units away from (2,0)

an opposite vertex will be $5\sqrt{2}$ units from (2,0)

use the distance formula ...

$\sqrt{(x_1-x_2)^2 + (y_1-y_2)^2}$