# Thread: Find the area of a parallelogram with vertices A(–4, 2), B(1, 6), C(15, 6), and D(10,

1. ## Find the area of a parallelogram with vertices A(–4, 2), B(1, 6), C(15, 6), and D(10,

Find the area of a parallelogram with vertices A(–4, 2), B(1, 6), C(15, 6), and D(10, 2).

A) 48 square units
B) 56 square units
C) 60 square units
D) 51 square units
E) 70 square units

2. Originally Posted by Leo34005
Find the area of a parallelogram with vertices A(–4, 2), B(1, 6), C(15, 6), and D(10, 2).

A) 48 square units
B) 56 square units
C) 60 square units
D) 51 square units
E) 70 square units
Start by plotting the given points and drawing the parallelogram. Now read this: Area of a Parallelogram

3. $\overrightarrow {AB} = \left\langle {5,4} \right\rangle \;\& \,\overrightarrow {AD} = \left\langle {14,0} \right\rangle$

Then $\text{Area}=\left\| {\overrightarrow {AB} \times \overrightarrow {AD} } \right\|$

4. Originally Posted by Plato
$\overrightarrow {AB} = \left\langle {5,4} \right\rangle \;\& \,\overrightarrow {AD} = \left\langle {14,0} \right\rangle$

Then $\text{Area}=\left\| {\overrightarrow {AB} \times \overrightarrow {AD} } \right\|$
This answer is correct but may be beyond the OP's current level of understanding.

Edit: OP = Original Poster.