Given thatYM = 3a, MZ = a+2, LM = 18 and XZ = 30, find a in the following diagram
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Cause they are similar triangles you can setup a ratio: $\displaystyle \frac{3a}{3a + (a + 2)} = \frac{18}{30} \Rightarrow \frac{3a}{4a + 2} = \frac{18}{30} $ Cross multiply:
Originally Posted by eXist Cause they are similar triangles you can setup a ratio: $\displaystyle \frac{3a}{3a + (a + 2)} = \frac{18}{30} $ yeah that is what i had but the other way round, in not sure if that is correct? Or can a figure be worked out for a?
Cross multiply from there: $\displaystyle (3a)(30) = (4a + 2)(18) $ $\displaystyle 90a = 72a + 36 $ $\displaystyle 18a = 36 $ $\displaystyle a = 2 $
Originally Posted by eXist Cross multiply from there: $\displaystyle (3a)(30) = (4a + 2)(18) $ $\displaystyle 90a = 72a + 36 $ $\displaystyle 18a = 36 $ $\displaystyle a = 2 $ ah i c thanks for detailed explanation
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