http://img16.imageshack.us/img16/4434/similar.jpg

Given thatYM = 3a, MZ = a+2, LM = 18 and XZ = 30, find a in the following diagram

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- Sep 1st 2009, 10:33 PMrealisticneed help with similar trinagle problem
http://img16.imageshack.us/img16/4434/similar.jpg

Given thatYM = 3a, MZ = a+2, LM = 18 and XZ = 30, find a in the following diagram - Sep 1st 2009, 11:46 PMeXist
Cause they are similar triangles you can setup a ratio:

$\displaystyle

\frac{3a}{3a + (a + 2)} = \frac{18}{30} \Rightarrow \frac{3a}{4a + 2} = \frac{18}{30}

$

Cross multiply: - Sep 1st 2009, 11:49 PMrealistic
- Sep 1st 2009, 11:51 PMeXist
Cross multiply from there:

$\displaystyle

(3a)(30) = (4a + 2)(18)

$

$\displaystyle

90a = 72a + 36

$

$\displaystyle

18a = 36

$

$\displaystyle

a = 2

$ - Sep 2nd 2009, 12:13 AMrealistic