for the function f1(x)= 2x-1
______
x+1
fn+1(x)= f1(fn(x)), n>=1
it can be shown that f35 = f5.
Find f28.
how can i get this?
If then . So the inverse function to is given by .
But if then the maps repeat with period 30. Therefore , where . I think that's the least painful way to calculate .
You can check this by using HallsofIvy's calculation for to see that . This turns out to be the same as . So in fact the s repeat with period 6.