Hi everyone! I don't quite understand what is the difference between these 2 questions and I was hoping if someone could explain it to me:
1. Ten children are to be divided into an A team and a B team of 5 each. The A team will play in one league and the B team in another. How many different divisions are possible? ANS: 10! / (5!5!)
I understand this solution because it's just following the formula.
2. In order to play a game of basketball, 10 children at a playground divide themselves into two teams of 5 each. How many different divisions are possible? ANS: [10! / (5!5!)] / 2!
I don't understand what the author means when he says that 'now the order of the two teams is irrelevant'. I still don't quite understand why I have to half the probability and what is the difference between this question and the one before. Can someone help me please?
Thanks in advance! ^^