Two questions...

#1

Oooopps! I made a big mistake. I had the answer right, I was just looking at the wrong problem in the back of my book. Im sorry about that.

#2

Let $\displaystyle f:\mathbb{R}\rightarrow\mathbb{R}$ be the function given by $\displaystyle f(x)=x^{2}$. Let $\displaystyle A=[-3,2]$ and $\displaystyle C=[1,5]$. Then $\displaystyle f(A\cup{C})=f([-3,5])=[0,25]$ and $\displaystyle f(A)\cup{f(C)}=[0,9]\cup{[1,25]}=[0,25]$.

I don't see how $\displaystyle f(A)=[0,9]$ and how $\displaystyle [0,25]$ comes from $\displaystyle f(A\cup{B})$. Where are those two zeros coming from?

Thanks for the help,

Dan