Thread: Mathematical Induction question

Hey there guys i was wondering if someone would be able to help me out. I have to get this done by tomorrow at 4:00PM so the faster the better. Here is the problem,
by mathermatical induction prove

n Sigma i=1 1/(2i-1)(2i+1) = n/2n+1

As you know the n is on top of the sigma and the i=1 at the bottom of the sigma

Thank you kn advance

Originally Posted by Evil Colt

Hey there guys i was wondering if someone would be able to help me out. I have to get this done by tomorrow at 4:00PM so the faster the better. Here is the problem,
by mathermatical induction prove

n Sigma i=1 1/(2i-1)(2i+1) = n/2n+1

As you know the n is on top of the sigma and the i=1 at the bottom of the sigma

Thank you kn advance

I assume you can do the first two steps. Then the trouble is in step 3, showing that the result is true for n + 1 assuming it's true for n.

So it boils down to showing that .

I think you can verify the base case for n=1.

So you assume the equality holds up to k. You must show it holds for k+1 for the induction to be complete.




this completes the induction.