4 players are dealt 13 cards from a 52 card deck. What is the probability that one player gets exactly 3 aces?
Shouldn't the total number of hands be $\displaystyle \binom{52}{13}$ ?
In which case it would be:
(number of 3 ace hands) / (total number of hands):
$\displaystyle
\binom{4}{3}\binom{48}{10}/\binom{52}{13} = 0.041
$