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Math Help - Help with tuple/set construction

  1. #1
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    Help with tuple/set construction

    I'm trying to develop a structure that will create a 1d index that refers to the contents of a 2d index, to try to flatten a table structure. For example, f:i --> (j,k). The table is:

    Help with tuple/set construction-table.gif

    You can see from this that Phi is a linear index that accesses the Alpha x Delta cell according to the Cartesian product. The set notation that I've put together follows:

    Help with tuple/set construction-phi-b.gif

    I still feel that this is wrong; any ideas about how this can be done?

    Because order is important, I wanted to create the C_Phi and C_Alpha,Delta as tuples.
    Last edited by RandomThinker; June 22nd 2009 at 07:25 AM.
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by RandomThinker View Post
    I'm trying to develop a structure that will create a 1d index that refers to the contents of a 2d index, to try to flatten a table structure. For example, f:i --> (j,k). The table is:

    Click image for larger version. 

Name:	Table.gif 
Views:	142 
Size:	3.7 KB 
ID:	11964

    You can see from this that Phi is a linear index that accesses the Alpha x Delta cell according to the Cartesian product. The set notation that I've put together follows:

    Click image for larger version. 

Name:	Phi-b.gif 
Views:	208 
Size:	4.1 KB 
ID:	11967

    I still feel that this is wrong; any ideas about how this can be done?

    Because order is important, I wanted to create the C_Phi and C_Alpha,Delta as tuples.
    LinearIndex=ColumnIndex + NumbColumns*(RowIndex-1)

    CB
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  3. #3
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    Thanks Capn...here is my latest incantation:

    Help with tuple/set construction-phi-d.gif

    Now here's the conundrum. Since the set C_Phi is correct in i and C_Alpha,Delta is correct in (j,k), then I can't help but think that the two can be combined to produce the set {(i,j,k),...,(m,n,p)} that would contain all the information that is needed to access the data linearly, according to the table above.
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