Results 1 to 2 of 2

Math Help - Combinatorics?

  1. #1
    Super Member fardeen_gen's Avatar
    Joined
    Jun 2008
    Posts
    539

    Combinatorics?

    There are two children C_1 and C_2. C_1 has 12 different toys and C_2 has 13 different toys. Find the number of ways in which C_1 and C_2 can exchange their toys in such a way that after exchanging they still have same number of toys but not the same set.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Senior Member pankaj's Avatar
    Joined
    Jul 2008
    From
    New Delhi(India)
    Posts
    318
     <br />
\binom{25}{12}-1<br />

    Let us take the toys from both of them.

    Now we select 12 toys and give them to C_{1} and the remaining 13 to C_{2} which can be done in \binom{25}{12}

    This also contain the ways in which they have their original set of toys.

    Hence,the answer is \binom{25}{12}-1
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. [SOLVED] Combinatorics.
    Posted in the Discrete Math Forum
    Replies: 16
    Last Post: July 20th 2010, 03:29 AM
  2. Combinatorics
    Posted in the Discrete Math Forum
    Replies: 3
    Last Post: June 18th 2010, 09:14 PM
  3. Combinatorics
    Posted in the Discrete Math Forum
    Replies: 3
    Last Post: June 3rd 2010, 06:24 PM
  4. combinatorics
    Posted in the Discrete Math Forum
    Replies: 1
    Last Post: May 1st 2010, 11:53 PM
  5. Combinatorics
    Posted in the Discrete Math Forum
    Replies: 2
    Last Post: October 10th 2009, 07:03 AM

Search Tags


/mathhelpforum @mathhelpforum