In how many different ways can $\displaystyle 8 $ coins be arranged on an $\displaystyle 8 \times 8 $ checkerboard so that no two coins lie in the same row or column?
So it would be $\displaystyle 64 \times 57 \times 52 \times 49 $?
In how many different ways can $\displaystyle 8 $ coins be arranged on an $\displaystyle 8 \times 8 $ checkerboard so that no two coins lie in the same row or column?
So it would be $\displaystyle 64 \times 57 \times 52 \times 49 $?
This would be for a $\displaystyle 4 \times 4 $ board. But is the reasoning correct?