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Thread: coins

  1. May 26th 2009, 06:23 PM #1
    Sampras
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    coins

    In how many different ways can 8 coins be arranged on an 8 \times 8 checkerboard so that no two coins lie in the same row or column?

    So it would be 64 \times 57 \times 52 \times 49 ?
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  2. May 26th 2009, 06:31 PM #2
    Sampras
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    Quote Originally Posted by Sampras View Post
    In how many different ways can 8 coins be arranged on an 8 \times 8 checkerboard so that no two coins lie in the same row or column?

    So it would be 64 \times 57 \times 52 \times 49 ?
    This would be for a 4 \times 4 board. But is the reasoning correct?
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  3. May 26th 2009, 07:43 PM #3
    TiRune
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    8 Lonely Rooks - Chess.com
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  4. May 26th 2009, 08:18 PM #4
    amitface
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    To summarize, there are 8 possible positions in the first row, 7 in the second, 6 in the third ...

    so 8!
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