# Hawaii

• May 26th 2009, 03:51 PM
Sampras
Hawaii
The Hawaiian alphabet consists of $12$ letters, the vowels $\text{a}, \ \text{e}, \ \text{i}, \ \text{o}, \ \text{u}$ and the consonants $\text{h}, \ \text{k}, \ \text{l}, \ \text{m}, \ \text{n}, \ \text{p}$ and $\text{w}$.

(a) How many different four-letter words can be constructed using the $12$-letter alphabet?

(b) How about with the English alphabet?

(c) What is the second and last letters are vowels and the other $2$ are consonants?

(d) What if the second and last letters are vowels, but there are no restrictions on the other $2$ letters?

So for (a) it would be $12^4$. For (b) it would be $26^4$. For (c) it would be $5^27^2$. And for (d) it would be $5^212^2$?
• May 26th 2009, 05:04 PM
amitface
Correct.