Hello BlahdkmA constant term is one that doesn't involve any variables - like and , for instance. In the example you quote, there are no constant terms - every term involves or or both. But in an expression like

there will a term that doesn't involve . You find it as follows:

Since the term outside the bracket is , the term in in the expansion of will result in the cancellation of the 's, and hence a constant term. This term is

So the constant term in the expansion of is .

The D's can be placed in 3 positions out of 5, and the R's in the remaining positions. So the number of possible arrangements is .B) Sandra is testing to see if she can tell the difference between diet pop, and regular pop. She knows there are 3 cups of diet pop, and 2 cups of regular pop, and she'll write the order which she believes the pop to be in. How many ways can record D(for Diet) and R(for Regular) if order matters?

This is only part of the answer - where you haveC)There are 8 non-fiction books, and 7 fiction books. You are to recieve two of them as a gift, how many combinations are possible if you are to recieve AT LEAST 1 fiction book?

-Is this as simple just figuring out how many combinations of 2 fiction books there are, and multiplying it by the combinations of 1 fiction book, 1 non-fiction book(which would be 56 right?)?exactlyone fiction book. You need to add to this the number of ways of choosing 2 fiction books from 7, which is . So the total number is .

Answer . See A above!D) How do you solve for a constant tern in the expansion of (x+2)^9?

Mucho Gracias to any and all help!

Grandad