I'm having some difficulties on how to show/prove this relation. Defined function: ⊕: by ⊕ Show that, ~ and ~ then ⊕ ~ ⊕ Grateful for any pointers, elaboration! Bit sorry for the wrong title...
Last edited by jokke22; May 12th 2009 at 05:01 AM. Reason: Misleading title
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your defined function looks fishy to me as its written N^2 x N -> N, although it takes N^2 x N^2 -> N^2 input... however, the relation to prove is easy as it's just addition of "vectors" or a coupled pair...
Sorry, a typo there it should be N^2*N^2->N^2
Originally Posted by TiRune your defined function looks fishy to me as its written N^2 x N -> N, although it takes N^2 x N^2 -> N^2 input... however, the relation to prove is easy as it's just addition of "vectors" or a coupled pair... Would you then just show that, since ⊕: And ⊕ = That ⊕ ⊕ I'm bad at proving these things.... Be gentle... Which is by defenition which is the same as
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