How many different bridge hands are there which contain 5 clubs, 4 diamonds, 3 hearts and 1 spade?

number of ways to pick 5 out of 13 clubs * number of ways to pick 4 out of 13 diamonds* number of ways to piuck 3 out of 13 hearts* number of ways to pick 1 out of 13 spades.

if you define a bridge hand to be non-reliant on order that is. so you have 4 sub problems. if you have to pick n out of m without order, that is n over m.

How many different bridge hands which contain 5, 4, 3 and 1 card in the four suits in any order?

take the previous example, and do it times the amount of ways to rearrange the 4 suits to the 4 numbers. Should be straightforward.

The probability of a bridge hand (13 cards) not containing any card of a suit?

This is the total amount of bridge-hands, divided by the total amount of bridge hands of only three colors. exactly the same way as the previous two questions, just define how much cards you can pick from and how much are in the bridge hand you want ignoring order.

How many ways three distinct numbers can be chosen from {1,2,3,4,5,6,7,8,9,10} so that no two are consecutive?

You can view this problem as follow. The amount of ways three distinct numbers can be chosen from {1,2,3,4,5,6,7,8,9,10} so that no two are consecutive is equal to: the amount of three distinct numbers MINUS the amount of ways you can pick three distinct numbers and two are consecutive PLUS the amount of ways you can pick three distinct numbers and ALL THREE are consecutive (these get counted twie in the two consecutive + free). The first should be easy, and you can solve the two consecutive and three consecutive by 'glueing' these together. instead of {,}{,}{,}{,}{,}{,}{,}{,}{,}{,} you get {,,,}{,}{,}{,}{,}{,}{,}{,}, {,}{,,,}{,}{,}{,}{,}{,}{,} etc., and the same goes for the two case but with an 'extra' freely to choose number.

How many ways in the range 1 - 1million are perfect squares, or divisible by 4 or 7?

If you mean how many numbers the question is rather simple: just take the root of 1 million, floor it and that's the amount of perfect squares. same goes for the divisions, just divide and floor. If you have to find the amount of numbers that satisfy ANY of these conditions, just add these and substract the numbers that have divisible by 4 or 7 in common (hint: divisible by 4*7), have perfect squares and divisible by 4 in common (hint: any even squared) and perfect squares and divisble by 7 in common (hint: 7 is prime), and PLUS 2*that have all three in common.

what do you mean by SSSSS(A(M(x,x),M(y,y))?

I think these questions belong in the high school forum and not the university forum though

If you need solutions for these questions instead of these overly directive directions feel free to ask.