[SOLVED] Proof - Can somebody please check my work

• Apr 25th 2009, 12:57 PM
spearfish
[SOLVED] Proof - Can somebody please check my work
Hi,

I am to prove the following:

If a, b, c are real numbers s.t. a & c are NOT 0, then there is a unique number x s.t. x/a + b/c = 1.

Ok, this is what I have:

Let a, b, c be reals s.t. x/a + b/c = 1 and a & c are NOT 0.

(x * 1/a) + (b * 1/c) = 1

a[ (x*1/a) = 1 - (b * 1/c) ]

x = a [ 1 - (b *1/c)]

Since b*1/c is an element of R & 1-b/c is also and element of R,

then a(1-b/c) is also an element of R.

So x is an element of R.

This seems pretty straight forward, but I just want to make sure that I am not approaching this wrong or am missing something in my proof. Thanks.
• Apr 25th 2009, 01:10 PM
Plato
That works as far as it goes. You have shown existence.
Now show uniqueness: $\displaystyle \frac{r}{a} + \frac{b}{c} = 1\,\& \,\frac{s}{a} + \frac{b}{c} = 1 \Rightarrow \quad r = s.$
• Apr 25th 2009, 01:29 PM
spearfish
will do! Thanks for help.