# Math Help - [SOLVED] A small city in Vermont has 11 men and 7 women..

1. ## [SOLVED] A small city in Vermont has 11 men and 7 women..

A small city in Vermont has 11 men and 7 women.
a) What is the maximum number of civil unions (that is, man-man, woman-woman, man-woman) that can be formed from this group
b) how many different ways can this maximum number of civil unions be formed?

for problem a) i figured it out: 11+7 = 18, 18/2 = 9 which is the maximum number of civil unions that can be formed from this group.

2. PLEASE NOTE: The reason of the deletions is that I misread the question so the answer and subsequent responses based on that mistake were useless.
The maximum number of civil unions among that group of eighteen people, regardless of sexual parings, is the same as the number of ways of dividing eighteen people in to nine groups of two each.

That number is: $\frac{18!}{\left(2^9\right) \left(9!\right)}$

3. ## really disappointed

Originally Posted by Plato
PLEASE NOTE: The reason of the deletions is that I misread the question so the answer and subsequent responses based on that mistake were useless.
The maximum number of civil unions among that group of eighteen people, regardless of sexual parings, is the same as the number of ways of dividing eighteen people in to nine groups of two each.

That number is: $\frac{18!}{\left(2^9\right) \left(9!\right)}$
I am really disappointed in your NOTE above .
One who posted this thread was a newbie as I noticed .