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Math Help - [SOLVED] A small city in Vermont has 11 men and 7 women..

  1. #1
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    Lightbulb [SOLVED] A small city in Vermont has 11 men and 7 women..

    A small city in Vermont has 11 men and 7 women.
    a) What is the maximum number of civil unions (that is, man-man, woman-woman, man-woman) that can be formed from this group
    b) how many different ways can this maximum number of civil unions be formed?

    for problem a) i figured it out: 11+7 = 18, 18/2 = 9 which is the maximum number of civil unions that can be formed from this group.

    problem b) is confusing so i need your help please..
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  2. #2
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    PLEASE NOTE: The reason of the deletions is that I misread the question so the answer and subsequent responses based on that mistake were useless.
    The maximum number of civil unions among that group of eighteen people, regardless of sexual parings, is the same as the number of ways of dividing eighteen people in to nine groups of two each.

    That number is: \frac{18!}{\left(2^9\right) \left(9!\right)}
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  3. #3
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    Unhappy really disappointed

    Quote Originally Posted by Plato View Post
    PLEASE NOTE: The reason of the deletions is that I misread the question so the answer and subsequent responses based on that mistake were useless.
    The maximum number of civil unions among that group of eighteen people, regardless of sexual parings, is the same as the number of ways of dividing eighteen people in to nine groups of two each.

    That number is: \frac{18!}{\left(2^9\right) \left(9!\right)}
    I am really disappointed in your NOTE above .
    One who posted this thread was a newbie as I noticed .
    So I used to help him with your answer and revealing the mistake you had made .
    Anyway I will decide what to do within next 24 hours .
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