f(n) = 2n^1.1 + 4nlogbase2(n)-8n
Determine a suitable function g(n) such that f(n) is teta(g(n)). Justify your answer.
Can i let g(n) = 2n^1.1 + 4nlogbase2(n)-8n, same function as f(n) and justify that f(n) grows at the same rate as g(n). Is it correct.