Show that A(1,n) = 2^n whenever n greater than or equal to 1

Problem :: Show that A(1,n) = 2^n whenever n greater than or equal to 1:

This is what i have so far:

proof by induction:

Basis Step: n =1 so we need to comput A(1,1) and A(1,1) equals 3

Inductive Step: Assume A(1, n-1) = 2^(n-1) and consider A(1, n)

I dont know if any of this is correct.. need some help here

Changing the text of a link

Quote:

Originally Posted by

**Moo** @ Grandad : the code is :

[url=http://.....]name for the link[/url]

(note that the part "name for the link" can include bbcode such as bold, color, etc...)

for example :

[url=http://www.mathhelpforum.com/math-help/][b][color=red]Your maths website[/color][/b][/url] gives :

**Your maths website**

Thanks, Moo. That worked fine when I just tested it! (And thanks too for an example of the use of [noparse], which has now become visible in the editor window. I'll add this posting to my 'Useful threads' folder, and hope I can remember where I put it!

Grandad