Hello! i am stuck on this recursive definition. I don't know what to do next.
Q: Give a recursive definition of the sequence {an}, n = 1, 2, 3, … if
a.) an = 4n – 2
b.) an = 1 + (-1)^(n)
c.) an = n(n + 1)
d.) an = n²
__________________________________________________ _____
I have this:
a.)
an = 4n – 2
a1 = 4(1) – 2
a1 = 4 – 2
a1 = 2
an = 4n – 2
a2 = 4(2) – 2
a2 = 8 - 2
a2 = 6
an = 4n – 2
a3 = 4(3) – 2
a3 = 12 - 2
a3 = 10
an = 4n – 2
a4 = 4(4) – 2
a4 = 16 - 2
a4 = 14
I can see they go up by 4 for part a, but do i leave it like this?
b.)
an = 1 + (-1)^(n)
a1 = 1 + (-1)^(1)
a1 = 1 – 1
a1 = 0
an = 1 + (-1)^(n)
a2 = 1 + (-1)^(2)
a2 = 1 + 1
a2 = 2
an = 1 + (-1)^(n)
a3 = 1 + (-1)^(3)
a3 = 1 – 1
a3 = 0
an = 1 + (-1)^(n)
a4 = 1 + (-1)^(4)
a4 = 1 + 1
a4 = 2
I can see the sequence going 0, 2, 0, 2, ... etc.
c.)
an = n(n + 1)
a1 = 1(1 + 1)
a1 = 1(2)
a1 = 2
an = n(n + 1)
a2 = 2(2 + 1)
a2 = 2(3)
a2 = 6
an = n(n + 1)
a3 = 3(3 + 1)
a3 = 3(4)
a3 = 12
an = n(n + 1)
a4 = 4(4 + 1)
a4 = 4(5)
a4 = 20
I am not sure on this one?


LinkBack URL
About LinkBacks




