• Mar 23rd 2009, 12:17 PM
gammaman
Given the partition P= {124; 5; 36} in a set of 6 elements,
How could you find the number of different partitions of 6 elements into 3 blocks?

What is this question asking me to do?
• Mar 23rd 2009, 12:27 PM
Plato
Quote:

Originally Posted by gammaman
Given the partition P= {124; 5; 36} in a set of 6 elements,
How could you find the number of different partitions of 6 elements into 3 blocks?

Are you saying that $\displaystyle \left\{ {\{ 1,2,4\} ,\{ 5\} ,\{ 3,6\} } \right\}$ is an example of a partition of $\displaystyle \left\{ {1,2,3,4,5,6} \right\}$?

Is this what you are looking for:http://mathworld.wolfram.com/Stirlin...condKind.html?
If so look at equation #7.
• Mar 23rd 2009, 01:34 PM
gammaman
Yes what is posted is a partition of a set of six elements 1......6.
• Mar 23rd 2009, 01:39 PM
gammaman
Actually I understand the first part of the question which says, how many ways can you partition a set of six elements. This is just done with a bell number. It is the second part which says "into 3 blocks" that I do not understand. {124; 5; 36} This is three blocks. 124 is a block 5 is a block and 36 is a block. As you questioned, 124 means 1,2,4.
• Mar 23rd 2009, 01:39 PM
Plato
Quote:

Originally Posted by gammaman
Yes what is posted is a partition of a set of six elements 1......6.

Well look at the webpage I gave you.
Scan down to formula (7).