Is it true that ? One-to-one??
Is is possible that ? Onto??
Define h: Z -> Z by h(x) = 7|x| – 6
a. Is h one-to-one? Explain.
b. Is h onto? Explain.
I'm having a hard time finding an explanation for this one. I think it is one-to-one, but not onto. Is this correct? An explanation would be appreciated
A function f is one-to-one if and only if whenever f(x) = f(y), x = y
A function f (from set A to B) is onto if and only for every y in B, there is at least one x in A such that f(x) = y
It is not one to one since
and I don't believe it would be onto then either