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  1. #1
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    Moved, New question

    Dear Professionals,

    I want help from your end, Could you please any one help me following question.
    If u help me, i will great full to you.

    1. A computer stores a number in a 16-bit word using floating-point arrangement. Given that the first bit is reserved for the sign, followed by 6 bits for the exponent having a biased of (+31) and the remaining bits for the mantissa with a hidden bit. Show how the computer stores -0.625.

    Regards

    Ravikumar
    Lecturer of Statistics
    BMA-Bangalore-37.
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  2. #2
    MHF Contributor

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    Quote Originally Posted by Ravikumar View Post
    Dear Professionals,

    I want help from your end, Could you please any one help me following question.
    If u help me, i will great full to you.

    1. A computer stores a number in a 16-bit word using floating-point arrangement. Given that the first bit is reserved for the sign, followed by 6 bits for the exponent having a biased of (+31) and the remaining bits for the mantissa with a hidden bit. Show how the computer stores -0.625.

    Regards

    Ravikumar
    Lecturer of Statistics
    BMA-Bangalore-37.
    -0.625= -\frac{5}{8}= -\frac{5}{2^3}= -5(2^{-3})
    This is negative so the first bit is 1.
    Since the exponent is represented with a bias of +31, this exponent is represented by -3+ 31= 29 which is 011101 in base2. 5 is 101 in base 2 so this number would be represented by 1011101000000101. That is the way I would do it. I confess that I don't know what "a hidden bit" is.
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  3. #3
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    Dear sir/madam,

    Thanks a lot for your co-operations. It will be very useful to me.

    Regards
    B.Ravikumar
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