1^3+2^3+...+n^3 = [n(n+1)/2]^2 n>= 1
If anyone has a link to write in mathematical nottaion on this forum, i will appreciate it, thanks.
Hello tokioThat's correct. I thought it was just the manipulation of the RHS that you couldn't do. The complete proof is:
Let be the propositional function:
Then
(as in my previous posting)
is , which is true. Hence .
Grandad
PS If you want to see the LaTeX that's been used to generate any of the expressions, just click on them and a little window will open showing you the code.