1^3+2^3+...+n^3 = [n(n+1)/2]^2 n>= 1

If anyone has a link to write in mathematical nottaion on this forum, i will appreciate it, thanks.

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- March 5th 2009, 09:41 AMtokioMathematical Induction help
1^3+2^3+...+n^3 = [n(n+1)/2]^2 n>= 1

If anyone has a link to write in mathematical nottaion on this forum, i will appreciate it, thanks. - March 5th 2009, 09:50 AMrunning-gag
Hi

Have a look to the LATEX tutorial in the LATEX forum

Let P(n) be

Check that P(1) is true

Suppose that P(k) is true and show that P(k+1) is true - March 5th 2009, 10:25 AMtokio
Thanks for the help, but i need help on the induction stage, when i do n+1. Here is what i have.

- March 5th 2009, 11:38 AMrunning-gag
- March 6th 2009, 10:58 AMtokio
- March 6th 2009, 12:21 PMGrandadProof by induction
- March 6th 2009, 07:22 PMtokio
- March 6th 2009, 11:08 PMGrandadProof by induction
Hello tokioThat's correct. I thought it was just the manipulation of the RHS that you couldn't do. The complete proof is:

Let be the propositional function:

Then

(as in my previous posting)

is , which is true. Hence .

Grandad

PS If you want to see the LaTeX that's been used to generate any of the expressions, just click on them and a little window will open showing you the code.